# Difference between revisions of "A Survey of Implicit Constraints in Primitives"

From BRL-CAD

Homovulgaris (talk | contribs) (ell, sph, tor) |
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# |B| > 0 | # |B| > 0 | ||

# |C| > 0 | # |C| > 0 | ||

− | # |A| | + | # |A| ~= |B| |

+ | # |A| ~= |C| | ||

+ | # |B| ~= |C| | ||

# A.B = 0 | # A.B = 0 | ||

# B.C = 0 | # B.C = 0 |

## Revision as of 08:00, 5 August 2008

## Contents

## Types of Implicit Parameters

At the level of constraint networks, calculations are done in terms of Variables or indpendent real values / floating point numbers. But in the construction of geometry these are clustered together in terms of implicit parameters. Typical implicit parameters are

**Vectors**- A 3 dimensional vector is a 3-tuple which is used to hold direction as well as magnitude. In BRL-CAD primitives, they may represent- Radius vectors ( Center of a sphere)
- Direction vectors (Direction of a plane)

## Types of Implicit Constraints

An enumeration of the set of contraints observed in the primitives below

**Modulus Comparison**: Comparison of the modulus of a vector to a real number ( 0 for non-negativity ) or the modulus of another vector**Perpendicularity of Vectors**

## Implict Constraints by Primitive

### ell (Ellipse)

Ellipse is built using the Center (radius vector V) and 3 Vectors (A, B, C st. |A| = radius) 2 types: Non-negativity/Modulus comparison, Perpendicularity Constraints:

- |A| > 0
- |B| > 0
- |C| > 0
- A.B = 0
- B.C = 0
- C.A = 0

### sph (Sphere)

Sphere is a particular case of the ellipse

Constraints: 2 types: Modulus comparison, Perpendicularity

- |A| > 0
- |B| > 0
- |C| > 0
- |A| ~= |B|
- |A| ~= |C|
- |B| ~= |C|
- A.B = 0
- B.C = 0
- C.A = 0

### tor (Torus)

Tor is built using the following input fields

V V from origin to center H Radius Vector, Normal to plane of torus. |H| = R2 A, B perpindicular, to CENTER of torus. |A|==|B|==R1 F5, F6 perpindicular, for inner edge (unused) F7, F8 perpindicular, for outer edge (unused)

Constraints: 2 types: Modulus comparison, Perpendicularity

- |A| = |B|
- A.B = 0
- B.H = 0
- H.A = 0
- 0 < |H| < |A|